Two men, starting at the same point, walk in opposite directions for 4 meters, turn left and walk another 3 meters. What is the distance between them?
2 meters
6 meters
10 meters
12.5 meters
14 meters

譯文：兩個(gè)男人,開始在同一點(diǎn),走在相反的方向4米,左轉(zhuǎn)走另一個(gè)3米。他們之間的距離是什么?
答案：這道題實(shí)際上是個(gè)幾何題，已知直角三角形的兩條直角邊，求斜邊的長。利用勾股定理就可以得到答案是10米。